# Hall Effect Experiment on Silver Using Leybold Apparatus

• Max Eilerson
In summary, the Leybold Hall Effect Apparatus for silver has a product ID of 58681 and dimensions of 0.064m in length, 0.02m in breadth, and 5E-5 m in thickness. The resistivity of silver is 1.89x10^-8 Ωm and the resistance is calculated to be 0.0012 Ω. However, the instructions suggest using a 20A (2V) current, which would require a high amount of current and potentially cause melting. As the contact resistances were measured to be in the microohm range, it is recommended to use a lower current to avoid damaging the expensive silver strip.
Max Eilerson
Using the leybold hall effect apparatus for silver http://www.leybold-didactic.com/phk/produkte.asp product ID: 58681. Dimensions
l = 0.064m (distance between contact), breadth 0.02m, and thickness 5E-5 m micrometers. Resistivity of silver $$\rho = 1.89x10^{-8} \Omega m$$
Resistance $$R = \rho\frac{L}{A}$$
$$R = 1.89x10^{-8} \Omega m \frac{0.064}{0.02.5x10^{-5}} = 0.0012 \Omega$$

The instructions say to put a 20 A (2V) current across the sample, but from Ohms law $$V = IR$$ to get a 2V potentia difference we would need to pump a huge current through it. We had the resistance the contact resistances measured and they were in the microohm range, I'm told.
Since we haven't got the leybold suggested power supply, my professor is reluctant to put 20A across it because the above suggests it would melt (the silver strip is pretty expensive). Obviously I'm missing somethign simple here but I'm not sure what.

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hmm, I guess for 20 A current the voltage is just going to reduce to 0.024 V.

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## 1. What is the Hall Effect Experiment on Silver Using Leybold Apparatus?

The Hall Effect Experiment on Silver Using Leybold Apparatus is a scientific experiment that demonstrates the Hall Effect, which is the production of a voltage difference across a conductor when a magnetic field is applied perpendicular to the current flow. This experiment specifically uses silver as the conductor and the Leybold Apparatus to measure the voltage and current.

## 2. Why is silver used as the conductor in this experiment?

Silver is used as the conductor in this experiment because it is a good conductor of electricity and has a high electron mobility, making it ideal for observing the Hall Effect. It also has a high resistance to oxidation, ensuring accurate and consistent results.

## 3. How does the Leybold Apparatus measure the Hall voltage?

The Leybold Apparatus measures the Hall voltage by placing the silver conductor in a magnetic field and measuring the voltage difference that is created perpendicular to the current flow. The apparatus uses a Hall probe, which consists of a thin strip of metal with a voltage gauge attached, to measure this voltage difference.

## 4. What are the main applications of the Hall Effect Experiment?

The Hall Effect Experiment has many important applications in various fields of science and technology. It is commonly used to measure the concentration of charge carriers in a material, determine the type of charge carriers (positive or negative), and study the properties of semiconductors. It also has practical applications in devices such as Hall sensors, which are used in electronic devices to detect magnetic fields.

## 5. How can the Hall Effect Experiment be used to study the properties of a material?

The Hall Effect Experiment can be used to study the properties of a material by measuring the Hall voltage at different magnetic field strengths and current densities. From these measurements, the Hall coefficient and charge carrier concentration can be calculated, providing valuable information about the material's electronic properties. This experiment can also be used to study the effects of temperature and impurities on a material's conductivity and carrier mobility.