Wavefunction
- 99
- 4
Homework Statement
The point of suspension of a simple pendulum of length l and mass m is constrained to move on
a parabola z = ax^2 in the vertical plane. Derive a Hamiltonian governing the motion of the
pendulum and its point of suspension. This is a two-dimensional problem.
Homework Equations
eq(1) H=T+U
The Attempt at a Solution
T=\frac{m}{2}[\dot{x}^2+\dot{z}^2]
U=mgz
eq(2) H = \frac{m}{2}[\dot{x}^2+\dot{z}^2]+mgz
Applying the constraint z=ax^2, \dot{z} = 2ax\dot{x}
H = \frac{m}{2}[\dot{x}^2+4a^2x^2\dot{x}^2]+mgax^2
The resulting Hamilton's equations I got were:
eq(3) \dot{p_x} = -(4ma^2x\dot{x}^2+2mgax) = -\frac{∂H}{∂x}
eq(4) \dot{x} = \frac{p_x}{m(1+4a^2x^2)} = \frac{∂H}{∂p_x}
and p_x = \frac{∂L}{∂\dot{x}} = m(1+4a^2x^2)\dot{x}
This problem seemed uncharacteristically easy, so I definitely appreciate anybody who checks it over (: Thank you in advance!