Wavefunction
- 99
- 4
Homework Statement
The point of suspension of a simple pendulum of length [itex]l[/itex] and mass [itex]m[/itex] is constrained to move on
a parabola [itex]z = ax^2[/itex] in the vertical plane. Derive a Hamiltonian governing the motion of the
pendulum and its point of suspension. This is a two-dimensional problem.
Homework Equations
eq(1) [itex]H=T+U[/itex]
The Attempt at a Solution
[itex]T=\frac{m}{2}[\dot{x}^2+\dot{z}^2][/itex]
[itex]U=mgz[/itex]
eq(2) [itex]H = \frac{m}{2}[\dot{x}^2+\dot{z}^2]+mgz[/itex]
Applying the constraint [itex]z=ax^2[/itex], [itex]\dot{z} = 2ax\dot{x}[/itex]
[itex]H = \frac{m}{2}[\dot{x}^2+4a^2x^2\dot{x}^2]+mgax^2[/itex]
The resulting Hamilton's equations I got were:
eq(3) [itex]\dot{p_x} = -(4ma^2x\dot{x}^2+2mgax) = -\frac{∂H}{∂x}[/itex]
eq(4) [itex]\dot{x} = \frac{p_x}{m(1+4a^2x^2)} = \frac{∂H}{∂p_x}[/itex]
and [itex]p_x = \frac{∂L}{∂\dot{x}} = m(1+4a^2x^2)\dot{x}[/itex]
This problem seemed uncharacteristically easy, so I definitely appreciate anybody who checks it over (: Thank you in advance!