Hamiltonian of the Half Harmonic Oscillator

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SUMMARY

The Hamiltonian for the half harmonic oscillator, defined by the potential \( V = \frac{1}{2}\omega^2mx^2 \) for \( x > 0 \) and \( V = \infty \) for \( x < 0 \), is given by \( H = \frac{1}{2}\omega^2mx^2 + \frac{P^2}{2m} \) for \( x > 0 \). The infinite potential at \( x < 0 \) effectively restricts the particle's motion to the region where \( x \geq 0 \), making the wave function zero in that region. Consequently, the Hamiltonian is not defined for \( x < 0 \) since the particle cannot exist there.

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Raxonan
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Given the half harmonic potential:

\begin{equation}V=\begin{cases}1/2\omega^2mx^2 & x > 0\\\infty & x < 0\end{cases}\end{equation}What will be the Hamiltonian of the half oscillator?I understand that for x>0 the Hamiltonian will be:

\begin{equation}H=\frac{1}{2}\omega^2mx^2+\frac{P^2}{2m}\end{equation}

But how do I find the Hamiltonian for the part when V = ∞?
 
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The infinite potential simply constrains the particle to the region x > 0. The wave-equation for x < 0 must be 0. I can't see how you could define a Hamiltonian for this.
 

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