Hamilton’s principle maximises potential energy?

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SUMMARY

Hamilton’s principle minimizes kinetic energy minus potential energy, establishing that with fixed kinetic energy, it maximizes potential energy. In scenarios where kinetic energy approaches zero, the Lagrangian becomes the negative of potential energy, leading to the conclusion that minimizing the Lagrangian equates to maximizing potential energy. Richard Feynman provides a detailed explanation in Figure 19.6 of his lectures, clarifying the relationship between kinetic energy and potential energy in this context.

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sentai
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Hamilton’s principle minimises kinetic energy minus potential energy, that is, with a fixed kinetic energy, Hamilton's principle maximises potential energy. What if we consider the limit that the kinetic energy or the mass/the inertia can be ignored then the lagrangian is solely the negative of potential energy. How to understand the potential energy needs to be maximised?
 
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Sorry, Fig 19-6 and its around explains it.
 
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anuttarasammyak said:
Sorry, Fig 19-6 and its around explains it.
Thanks for pointing it out. Then how should we understand the limit of KE->0, then min(L)=-max(PE)?
 
As Feynman stated we are looking for the path KE-PE integral on which should be extreme.
KE=0 takes place at the top of trajectory in Fig 19-6 but I do not think considering such "limit of KE->0" is meaningful.
 

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