Hang time, range, maximum height

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itsmarasilly
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Homework Statement


Find the ball's hang time, range, and maximum height.
A player kicks a football from ground level with an initial velocity of 27.0 m/s, 60.0° above the horizontal. Find the ball's hang time, range, and maximum height. Assume air resistance is negligible.


Homework Equations


Range = Initial Velocity ^ 2 /9.8
Height = (Initial Velocity)(Sin)^2/ (2)(9.8)


The Attempt at a Solution



I'm not sure if these equations are correct.
 
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Hi itsmarasilly,

itsmarasilly said:

Homework Statement


Find the ball's hang time, range, and maximum height.
A player kicks a football from ground level with an initial velocity of 27.0 m/s, 60.0° above the horizontal. Find the ball's hang time, range, and maximum height. Assume air resistance is negligible.


Homework Equations


Range = Initial Velocity ^ 2 /9.8

This does not look right; it is missing a trig factor. Do you see what this formula needs to be?

Height = (Initial Velocity)(Sin)^2/ (2)(9.8)

This is not correct (although you might just have a typo in your equation). In particular, what is being squared here?
 
the 60 degrees? would it be put in the calculator as sin(60^2) or sin(60)^2, does it make a difference?
 
itsmarasilly said:
the 60 degrees? would it be put in the calculator as sin(60^2) or sin(60)^2, does it make a difference?

The vertical component of your velocity is 27 * Sin 60. That's what you square.