Harmonic Functions: Why n>2 Condition Imposed

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Discussion Overview

The discussion revolves around the conditions under which the function \( f:\mathbb{R}^n \rightarrow \mathbb{R} = |X|^{2-n} \) is considered harmonic, specifically focusing on the requirement that \( n > 2 \). Participants explore the implications of this condition and question whether harmonicity holds for other values of \( n \), particularly \( n = 1 \).

Discussion Character

  • Debate/contested
  • Technical explanation

Main Points Raised

  • One participant asserts that the function is harmonic only for \( n > 2 \) and questions why this condition is necessary.
  • Another participant points out that the domain should be \( \mathbb{R}^n \setminus \{ 0 \} \) for the function to be defined at all points, particularly at 0.
  • A participant expresses confusion about why \( n = 1 \) would not be valid and seeks clarification on the harmonicity of the function in that case.
  • There is a suggestion to explore the behavior of the function when \( n = 1 \) to determine if it is harmonic.
  • One participant claims that for \( n = 1 \), the function satisfies the Laplace equation, implying it is harmonic, yet questions the necessity of the \( n > 2 \) condition as seen in various texts.
  • Another participant emphasizes the definition of harmonic functions as those that are continuously differentiable twice and satisfy the Laplace equation, suggesting further exploration of the criteria for harmonicity.

Areas of Agreement / Disagreement

Participants express differing views on the harmonicity of the function for \( n = 1 \) and the necessity of the condition \( n > 2 \). The discussion remains unresolved regarding the implications of these conditions.

Contextual Notes

Participants note the importance of the domain of the function and the definition of harmonic functions, but there are unresolved questions regarding the behavior of the function in lower dimensions and the specific reasons for the imposed condition.

praharmitra
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the function [tex]f:\Re^n \rightarrow \Re = |X|^{2-n}[/tex] is harmonic, but only for n > 2.

why is the condition n > 2 imposed. Isn't harmonic for all values of n??
 
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Shouldn't the domain be [tex]\mathbb{R}^n\setminus \{ 0 \}[/tex]? Otherwise, said f could not even exist at 0, and hence is clearly not harmonic.
 
ya I'm sorry that is the domain...my mistake...

but still, why shoud n>2, why can't n = 1?..

note: n stands for dimension of the space and hence is an integer >=1
 
oh, is this classical physics? ;-)

Try what happens if n=1, is the function harmonic then?
 
of course it is classical physics. It plays a MAJOR role in electromagnetic theory. and the potential formulation of the theory.

for n = 1, it is harmonic as laplacian(|X|) = 0 right? so it satisfies.

but then, why put the condition n > 2. I have seen it in many books
 
well then calculus problems are classic physics problems aswell. Just trying to make sure you get help.

Now harmonic functions are functions which are continuously differentiable twice and satisfy Laplace equation.

So play around with the criterion for twice continuously differentiable.
 

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