A bungee jumper undergoes simple harmonic motion with amplitude 6.9 m and frequency 0.115 Hz. Assume the bungee jumper follows the simple harmonic motion equation x=A\cos (\omega t).
Find the velocity of the jumper at 0.25s
The Attempt at a Solution
Found the angular velocity by multiplying the frequency by 2pi,
then plugged my values into the harmonic motion equation to find the x value, and divide by the time interval to find the velocity, but the homework says thats the wrong answer.