Harmonic Oscillator- Is this correct?

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SUMMARY

The shortest time required for a harmonic oscillator to move from position x = A to x = A/2 is calculated to be t = T/6, where T represents the period of the oscillator. The solution utilizes the equation x(t) = A cos(ωt) and identifies that at x = A/2, the corresponding angle is π/3 radians. This confirms that the time fraction of the period is 1/6, leading to the conclusion that the time taken is one-sixth of the total period.

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  • Knowledge of the relationship between angular frequency and period
  • Ability to manipulate equations involving cosine functions
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  • Explore the concept of energy conservation in harmonic oscillators
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Homework Statement


[/B]
What is the shortest time required for a harmonic oscillator to move from ##x = A## to ##x = \frac{A}{2}##? Express your answer in terms of the period ##T##.

Homework Equations


[/B]
##x(t)=Acos(\omega t)=Acos(2\pi\frac{t}{T})##

The Attempt at a Solution



##A=Acos(0)## which means ##\frac{t}{T}=## whole number
##\frac{A}{2}=Acos(\frac{\pi}{3})## which means ##\frac{t}{T}=\frac{1}{6}##
##t=\frac{T}{6}##
 
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Very good. It looks correct to me.
 

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