Harmonic Series: Is ∑(1/ k+1 ) Divergent?

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Homework Help Overview

The discussion revolves around the convergence of the series ∑(1/(k+1)) compared to the harmonic series ∑(1/k). Participants are exploring whether the former is also divergent like the latter.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Some participants attempt to clarify the definitions of the series involved and question the notation used. There is discussion about the relationship between the two series and the implications of their divergence.

Discussion Status

Participants are actively questioning the assumptions regarding the series and their divergence. Some guidance has been offered regarding writing out the terms of the series to better understand their relationship.

Contextual Notes

There is a note regarding the starting index of the series, emphasizing that starting from k=0 is problematic due to division by zero. This has led to clarifications about the correct formulation of the series.

foo9008
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Homework Statement


i know that k = 0 to∞∑(1/ k) is harmonic series( we know that the sum is divergent) , how about ∑(1/ k+1 ) ?

Homework Equations

The Attempt at a Solution


in my opinion , it's also harmonic series , because the sum is divergent . Am i right ?
 
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foo9008 said:

Homework Statement


i know that k = 0 to∞∑(1/ k) is harmonic series( we know that the sum is divergent) , how about ∑(1/ k+1 ) ?

Homework Equations

The Attempt at a Solution


in my opinion , it's also harmonic series , because the sum is divergent . Am i right ?

Note: the series cannot be ##\sum_{k=0}^{\infty} 1/k## because the first term would be 1/0. However, starting at ##k = 1## is OK.

Do you mean that one of the series is ##\sum_{k=1}^{\infty} 1/k## and the other is ##\sum_{k=1}^{\infty}(\frac{1}{k}+1)##? That is what you wrote. Did you really mean ##\sum_{k=1}^{\infty} 1/(k+1)## for the second series? If so, use parentheses, like this: 1/(k+1).

Anyway, just write out the first first few terms of both of your series, to see how they are related.

When you say "it's also harmonic series , because the sum is divergent" you have it backwards: it is not harmonic because it is divergent; it is divergent because it is harmonic. (Lots of divergent series are not at all harmonic.)
 
Ray Vickson said:
Note: the series cannot be ##\sum_{k=0}^{\infty} 1/k## because the first term would be 1/0. However, starting at ##k = 1## is OK.

Do you mean that one of the series is ##\sum_{k=1}^{\infty} 1/k## and the other is ##\sum_{k=1}^{\infty}(\frac{1}{k}+1)##? That is what you wrote. Did you really mean ##\sum_{k=1}^{\infty} 1/(k+1)## for the second series? If so, use parentheses, like this: 1/(k+1).

Anyway, just write out the first first few terms of both of your series, to see how they are related.

When you say "it's also harmonic series , because the sum is divergent" you have it backwards: it is not harmonic because it is divergent; it is divergent because it is harmonic. (Lots of divergent series are not at all harmonic.)
i mean second one , IMO , it is also harmonic ... , am i right ?
 
foo9008 said:
i mean second one , IMO , it is also harmonic ... , am i right ?

Have you tried to write out the first few terms of both series to see how they differ? If you do, you can answer your own question.
 
The infinite sum of 1/(k+1), with k starting from 1, is the same as the infinite sum of 1/k, with k starting from one minus 1. Follow Ray Vickson's advice to see this.
 
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