(adsbygoogle = window.adsbygoogle || []).push({}); Having a massive brain fart... SIMPLE "molarity -> molality" conversion...

This isn't even a homework question per se, I'm just trying to understand how the question converted the molarity to the molality value, via the density given. I just got a different value of molality when trying to solve for it manually... and am pretty sure I did something stupid.

1. The problem statement, all variables and given/known data

If the osmotic pressure of a6.02×10was found to be 4.05 atm at 20°C.^{-2}M aqueous solution of Ca(NO_{3})_{2}Note that the corresponding molality would be 6.10×10, given that the density of the solution is 0.997 g/cm^{-2}m^{3}....

2. Relevant equations

None.

3. The attempt at a solution

Okay.... so the question tells me it has a molality of 6.10×10^{-2}m,

So if I want to solve for that myself, I would start off with the given molarity, right? So it would be6.02×10then multiply it by the density of solution, 0.997g/cm^{-2}M^{3}, or in other words,0.997kg/1L... and then we're done, right?

So:

6.02×10multiply^{-2}mol/L1L/0.997kg=6.04x10^{-2}

... but the question tells me it's6.10×10.... and I have no idea why I'm not getting that value.^{-2}m

I don't know what's going wrong here... I'm sure I am missing something dead simple...

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# Homework Help: Having a massive brain fart SIMPLE molarity -> molality conversion

**Physics Forums | Science Articles, Homework Help, Discussion**