Having toruble remembering series and sequences in algebra

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SUMMARY

The discussion focuses on the challenges of remembering formulas for arithmetic series and sequences in algebra. Key formulas mentioned include the sum of an arithmetic series, represented as Sn = n/2 (a1 + an), and the derivation of the sum of the first n natural numbers, 1 + 2 + 3 + ... + n = n(n + 1)/2. Participants emphasize the importance of understanding the derivations of these formulas and suggest using resources like used algebra textbooks for better comprehension. Additionally, they recommend practicing exercises to reinforce memory of the formulas.

PREREQUISITES
  • Understanding of arithmetic sequences and series
  • Familiarity with basic algebraic concepts
  • Knowledge of the common difference in sequences
  • Ability to derive mathematical formulas
NEXT STEPS
  • Study the derivation of the arithmetic series sum formula
  • Practice problems involving arithmetic sequences
  • Explore online tutorials specifically focused on arithmetic series
  • Acquire a used algebra textbook for comprehensive examples and exercises
USEFUL FOR

Students struggling with algebra, particularly those learning about arithmetic sequences and series, as well as educators seeking to provide additional resources for their students.

touma
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I am trying to remember the formulas and ways to do this but I am have much trouble! Please help! Thank you!
1) Find the sum of the first 50 terms 1, 8, 15,... using the sum of an arithmetic series formula.

2) Find the sum of the n terms of the arithmetic sequence a1 = 7, a12 = 29, n = 12.
 
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- Warren
 
I'm not asking anyone to do my homework for me! I did the rest of my sheet already but I can't figure out these two! My class doesn't have a textbook
 
touma said:
I am trying to remember the formulas and ways to do this but I am have much trouble! Please help! Thank you!
1) Find the sum of the first 50 terms 1, 8, 15,... using the sum of an arithmetic series formula.

2) Find the sum of the n terms of the arithmetic sequence a1 = 7, a12 = 29, n = 12.

Learn the derivations of the formulas if you have trouble remembering the formulas. This could help you to remember the formulas. For arithmetic series & sequences, even just remembering the formulas should not be very difficult. Study more; do more exercises.
 
I just don't have the formulas. I looked at online tutorals and I got confused by everything. I think the formula for the first is Sn = n/2 (a1 + an) but i am not sure. I have no idea for the second one
 
touma said:
I just don't have the formulas. I looked at online tutorals and I got confused by everything. I think the formula for the first is Sn = n/2 (a1 + an) but i am not sure. I have no idea for the second one
Buy a used book; they are cheap. No more than $2 at a public library used book depository can yield any of a good set of intermediate or college algebra textbooks. These books are very easy to find in used supplies. If the book is 20 or 30 or more years old, the concepts and skills will be the same; so will the formulas, all of which will usually be derived for you in the book.
 
You wouldn't happen to have any examples of arithmetic series?
 
Emmanuel114 said:
You wouldn't happen to have any examples of arithmetic series?

Just any example?

Like this:
1+2+3+4+5+6+7+8+9+10=55=(10)(10+1)/2

In general an arithmetic series arises by adding together the terms in an arithmetic sequence.

In an arithmetic sequence we start with an initial term let's call it a, and then to get the next term we add a number (I think usually called the common difference, I'm not positive though) let's call it d.

So we have a sequence of numbers a0,a1,a2...an

So that
a0=a
And
an=a+n*d

To clarify why d is usually called a common difference consider the difference

an-an-1=(a+n*d)-(a+(n-1)*d)=(a-a)+(n*d-(n-1)*d)=d.

Then from this sequence we get an arithmetic series by adding up all of these terms, so the series is a0+a1+a2+...+an.

It would be a good exercise to derive the sum of a general arithmetic series from the sum of the first n natural numbers:

1+2+3+...+n=n(n+1)/2
 
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