Having trouble with complex quadratic equations

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
5 replies · 3K views
Jeff Cook
Messages
41
Reaction score
0
All,

I am not sure how to handle this situation with complex numbers. Can you help?

Q = A^2 + ABi

Where Q is a complex number.

Can we not solve for A if we know Q and Bi using a quadratic equation?

0 = A^2 + ABi + -Q

Let...

Q = 455
Bi = -22

And in this case I do know that A = 35. However...

When,

a = 1
b = -22
c = -455

Solving...

A = ( -1 +/- Sqrt { 1 - ( 4 * -22 * -455 )}) / 2

I do not get A = 35. Any idea why and what I may be doing wrong?

Thanks,

Jeff
 
Physics news on Phys.org
You messed up while substituting values into the quadratic formula.
 
Show...

Hurky,

Could you show me what you mean? Where did I mess up?

J
 
You have confused what the problem is. You are using A in place of X, then you turn around and act like it is something else.
 
Jeff Cook said:
Hurky,

Could you show me what you mean? Where did I mess up?

J
There are 5 places in the quadratic formula where you need to substitute a number. You got three of them wrong. You know the quadratic formula, right? The solutions to

ax² + bx + c = 0

are

[tex]\frac{-b \pm \sqrt{b^2 - 4ac}}{2a},[/tex]

right? Just double check your work!


robert Ihnot said:
You have confused what the problem is. You are using A in place of X, then you turn around and act like it is something else.
I'm quite sure he did not make that mistake.
 
Oops...

Hurky,

Okay, I was placing a in place of b in the quadratic equation. Stupid mistake. Thanks greatly. Now I get the correct answer.

Jeff