"Heat current" on a microscopic level

[zb23]

What is the difference on microscopic level between electric current and heat current(conduction)?

 

[vanhees71]

Electric current describes a transport of electric charge and the heat current a transport of heat energy.

 

[Charles Link]

It may be of interest that with electric current, there is a flow of charged particles, (electrons in the direction opposite the current flow), and the result is magnetic fields are produced (Biot-Savart), and capacitor plates can become charged.
With heat current, there is no overall transport of particles. It is simply a flow of the kinetic energy.

 

[zb23]

Electric current describes a transport of electric charge and the heat current a transport of heat energy.

Please understand my question more deeply

 

[vanhees71]

Then you have to more clearly express your question :-).

 

[zb23]

It may be of interest that with electric current, there is a flow of charged particles, (electrons in the direction opposite the current flow), and the result is magnetic fields are produced (Biot-Savart), and capacitor plates can become charged.
With heat current, there is no overall transport of particles. It is simply a flow of the kinetic energy.

I am not talking about those trivial stuff

 

[zb23]

Then you have to more clearly express your question :-).

It doesn't matter. Sorry for bothering you.

 

[Charles Link]

I am not talking about those trivial stuff

It seems like a good question you asked. Without the details of the "trivial stuff", there perhaps isn't much difference between electric current flow and energy flow.
e.g. if the charge balances in the conductor carrying current, how do you know that there is a flow of charge as opposed to a flow of energy/heat ?

 

[etotheipi]

Mathematically the description of each isn't too different. For electric current one case you could consider is where Ohm's law holds i.e. the electric current density can be shown to satisfy$$\mathbf{j}_e = -\sigma \nabla \phi$$For heat current, if you assume that there is no convection component (i.e. if we assume there is only a Fick's law diffusion component) to the heat current density, you can describe it as$$\mathbf{j}_h = -D\nabla T$$In this way there is a correspondence between $\phi \leftrightarrow T$ and $\sigma \leftrightarrow D$

 

[hutchphd]

Caloric does not carry charge?

 

[Dale]

Please understand my question more deeply

Please put more effort into your question. The answer you got was the answer to the question you asked. We cannot read your mind, so we don’t know what deep question you are asking unless you put in the effort to formulate it clearly and write it down. All we can do is respond to what you write. We are physicists, not psychics.