Telemachus
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Hi. I'm trying to solve the heat equation with the initial boundary conditions:
u(0,t)=f_1(t)
u(x_1,t)=f_2(t)
u(x,0)=f(x)
0<x<x_1
t>0
And the heat equation: \frac{\partial u}{\partial t}-k\frac{\partial^2 u}{\partial x^2}=0
So when I make separation of variables I get:
\nu=X(x)T(t)
\frac{T'(t)}{T(t)}=k\frac{X''(x)}{X(x)}
Then I have to solve for X
kX''(x)-\lambda X(x)=0
With the initial boundary conditions
X(0)=f_1(t)
X(x_1)=f_2(t)
And for T:
T'(t)-\lambda T(t)=0
With initial value:
T(0)=f(x)
How should I proceed from here? I'm not sure how to make this accomplish the boundary conditions.
Bye, thanks.
u(0,t)=f_1(t)
u(x_1,t)=f_2(t)
u(x,0)=f(x)
0<x<x_1
t>0
And the heat equation: \frac{\partial u}{\partial t}-k\frac{\partial^2 u}{\partial x^2}=0
So when I make separation of variables I get:
\nu=X(x)T(t)
\frac{T'(t)}{T(t)}=k\frac{X''(x)}{X(x)}
Then I have to solve for X
kX''(x)-\lambda X(x)=0
With the initial boundary conditions
X(0)=f_1(t)
X(x_1)=f_2(t)
And for T:
T'(t)-\lambda T(t)=0
With initial value:
T(0)=f(x)
How should I proceed from here? I'm not sure how to make this accomplish the boundary conditions.
Bye, thanks.
Last edited: