Heat equation with nonhomogeneous boundary conditions

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SUMMARY

The discussion centers on solving the heat equation with nonhomogeneous boundary conditions, specifically the equation \(\frac{\partial u}{\partial t} = k\frac{\partial^2u}{\partial x^2}\) with boundary conditions \(u(0,t) = A(t)\) and \(u(L,t) = 0\). Participants highlight the challenge of convergence of the Fourier sine series at \(x = 0\) unless \(A(t)\) is zero, which complicates term-by-term differentiation. The consensus is that the non-zero boundary condition at \(x = 0\) creates a fundamental issue in applying the Fourier sine series method.

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  • Understanding of the heat equation and its boundary conditions
  • Familiarity with Fourier sine series and their properties
  • Knowledge of differential equations and term-by-term differentiation
  • Basic calculus, particularly integration techniques
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  • Learn about convergence criteria for Fourier series, specifically in the context of boundary value problems
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Students and researchers in applied mathematics, particularly those focusing on partial differential equations, heat transfer problems, and Fourier analysis.

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Homework Statement



Consider
\frac{\partial u}{\partial t} = k\frac{\partial^2u}{\partial x^2} subject to
u(0,t) = A(t),\ u(L,t) = 0,\ u(x,0) = g(x). Assume that u(x,t) has a Fourier sine series. Determine a differential equation for the Fourier coefficients (assume appropriate continuity).

Homework Equations



Coefficients of the Fourier sine series of f(x):
B_n = \frac{2}{L}\int_0^L f(x)\sin(n\pi x/L)\ dx

The Attempt at a Solution



I'm stuck just getting a start. The problem is that u(x,t) will not converge to its Fourier sine series at x = 0 unless A(t) is identically zero. This also kills the ability to perform term-by-term differentiation on the FSS. It seems impossible to impose the boundary condition at x = 0. Thoughts?
 
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BUMP.

I also have this same question. I was also stuck at the same point. Since by assumption,
u(x,t) ≈ \sum B_n(t)sin ( \frac{n \pi x}{L})
then it follows that you can't differentiate since it is a sine series. Sine series implies it must be continuous and u(0,t)=u(L,t)=0. However, u(0,t)=A(t).

I'm not sure how to approach this problem.
 

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