Heat Needed to Boil 237mL Water vs Starting Car

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The discussion centers on calculating the heat required to boil 237 mL of water compared to the energy used to start a car. The relevant formula is ΔH = mcΔt, where ΔH represents the change in heat, m is the mass, c is the specific heat capacity of water, and Δt is the change in temperature. The energy required to boil the water is estimated at 216,000 J, while the energy needed to start the car remains unspecified. Key concepts include the initial temperature of the water and the specific heat capacity.

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a) how much more heat is used to boil 237 mL of water as opposed to starting the car?

b) what major concept/finding was overlooked while solving this problem?

I think this has something to do with delta H = mc(delta t) but idk
 
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Mango12 said:
a) how much more heat is used to boil 237 mL of water as opposed to starting the car?

Starting what car?

Mango12 said:
...idk

You are on a math forum doing things that have some merit, not texting your buddy about some he said/she said drama that happened in the parking lot outside the high school at last night's sock hop or posting selfies and other such tomfoolery on social media...please don't use text abbreviations when posting here. (Shake)

http://unaccomplishedangler.com/wordpress/wp-content/uploads/2015/02/Oldmanshakefist.jpg
 
MarkFL said:
Starting what car?
You are on a math forum doing things that have some merit, not texting your buddy about some he said/she said drama that happened in the parking lot outside the high school at last night's sock hop or posting selfies and other such tomfoolery on social media...please don't use text abbreviations when posting here. (Shake)

my apologies. And I believe it was a car in a previous problem..but I don't have my paper with me to give the exact problem and it's very confusing.
 
Mango12 said:
my apologies. And I believe it was a car in a previous problem..but I don't have my paper with me to give the exact problem and it's very confusing.

When you gather together all the information relating to and necessary for working this problem, then please post it in this thread. Until then, there's not much anyone can do to help. :)
 
MarkFL said:
When you gather together all the information relating to and necessary for working this problem, then please post it in this thread. Until then, there's not much anyone can do to help. :)

okay..I will. But a side note..he said in order to solve this I need to know 2 key properties of water...do you have an idea of what he means?
 
Mango12 said:
a) how much more heat is used to boil 237 mL of water as opposed to starting the car?

b) what major concept/finding was overlooked while solving this problem?

I think this has something to do with delta H = mc(delta t) but idk
How much more heat is given off by heating 237mL of water with 216,000J than is used to start the car? I don't have the value of the energy to start the engine, but does anyone know how I could go about solving this if I did?
 
Mango12 said:
a) how much more heat is used to boil 237 mL of water as opposed to starting the car?

b) what major concept/finding was overlooked while solving this problem?

I think this has something to do with delta H = mc(delta t) but idk

Mango12 said:
How much more heat is given off by heating 237mL of water with 216,000J than is used to start the car? I don't have the value of the energy to start the engine, but does anyone know how I could go about solving this if I did?

Hi Mango12! ;)

That actually seem to be different questions.
In your original problem statement we were boiling 237 mL of water.
That means we have:
$$V = 237\text{ mL} \\ \Delta t = 100^\circ\text C - t_{initial}$$
If we know what $t_{initial}$ is, we can calculate the heat required to boil the water.
Can we perhaps assume we start at room temperature ($20^\circ \text C$)?
Or is there perhaps an initial temperature given when starting the car?In your last response we seem to have a different question with:
$$V = 237\text{ mL} \\ \Delta H = 216,000\text{ J}$$
Or is that $\Delta H$ perhaps the heat given off when starting the car?Additionally we have the formula:
$$\Delta H = mc\Delta t$$
where $\Delta H$ is the change in heat, $m$ is the mass, $c$ is the specific heat capacity of water, and $\Delta t$ is the change in temperature.
Do you perchance have $c$ as a constant?

To calculate $m$, we can use:
$$m = \rho V$$
where $\rho$ is the density of water. Do you have that as a constant?After that we can apply the formula.

We'll get to (b) afterwards, since there are some conditions when applying the formulas.
 
I like Serena said:
Hi Mango12! ;)

That actually seem to be different questions.
In your original problem statement we were boiling 237 mL of water.
That means we have:
$$V = 237\text{ mL} \\ \Delta t = 100^\circ\text C - t_{initial}$$
If we know what $t_{initial}$ is, we can calculate the heat required to boil the water.
Can we perhaps assume we start at room temperature ($20^\circ \text C$)?
Or is there perhaps an initial temperature given when starting the car?In your last response we seem to have a different question with:
$$V = 237\text{ mL} \\ \Delta H = 216,000\text{ J}$$
Or is that $\Delta H$ perhaps the heat given off when starting the car?Additionally we have the formula:
$$\Delta H = mc\Delta t$$
where $\Delta H$ is the change in heat, $m$ is the mass, $c$ is the specific heat capacity of water, and $\Delta t$ is the change in temperature.
Do you perchance have $c$ as a constant?

To calculate $m$, we can use:
$$m = \rho V$$
where $\rho$ is the density of water. Do you have that as a constant?After that we can apply the formula.

We'll get to (b) afterwards, since there are some conditions when applying the formulas.

Hi! Thanks for replying, but I figured it out on my own before I saw your reply.
 

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