Heat of Reaction: NaOH & HCl | Expert Advice Needed

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SUMMARY

The discussion centers on the heat of reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl). When 5.5g of NaOH is added to 200ml of 1.0 mol/l HCl, the heat evolved is calculated based on the enthalpy of the reaction. If 11.0g of NaOH is used instead, the reaction will produce more heat due to the increased amount of reactant, as the enthalpy is directly related to the quantity of starting materials. The molar weight of NaOH is 40g/mol, indicating that 5.5g corresponds to approximately 0.14 mol, while 0.2 mol of HCl is present.

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msdel
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I conducted an expereiment where I added 5.5g of NaOH into 200ml of 1.0 mol/l of HCl. I've done all the calculations required but there is a questoin I am just not sure about. It asked if i was to add 11.0g of NaOH instead of the 5.5g i used would this have an effect on the amount of heat evolved? I was thinking that the heat evolved would stay the same...

Can anyone help me understand this one?

Thanks
 
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Look up the heat of formation data for HCL and NaOH. If the sum of those two is negative then the enthalpy of the reaction will decrease if you use twice as much NaOH since the enthaply of a reaction is directly related to the amount of starting material you use. If the sum of those two is positive then the enthalpy of the reaction will increase.
 
Last edited:
Since NaOH has a mol. wt. of 40g/mol, 5.5g of it is only about .14 mol. You used .2 mol of HCl, so adding more NaOH would cause a further reaction. This would increase the heat evolved.
 

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