Heat produced when a dielectric is inserted into a capacitor slowly

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SUMMARY

When a dielectric slab with dielectric constant k is inserted into a charged capacitor connected to a battery, heat is produced due to the work done by the battery to increase the charge on the capacitor. The energy produced by the battery is equal to the increase in potential energy of the capacitor plus the heat generated. In an ideal scenario with no internal resistance in the battery, the heat produced would be zero, as all energy would contribute to the increase in potential energy. However, real batteries possess finite internal resistance, which affects the total heat generated during this process.

PREREQUISITES
  • Understanding of capacitor charging and discharging principles
  • Knowledge of dielectric materials and their properties
  • Familiarity with electrical circuits and battery characteristics
  • Basic concepts of energy conservation in electrical systems
NEXT STEPS
  • Study the effects of dielectric materials on capacitor performance
  • Learn about internal resistance in batteries and its impact on circuit behavior
  • Explore the relationship between energy, work, and heat in electrical systems
  • Investigate real-world applications of capacitors with dielectrics in electronic devices
USEFUL FOR

Electrical engineers, physics students, and anyone interested in understanding the thermal effects of dielectrics in capacitors and their implications in circuit design.

aryan pandey
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if a capacitor is connected to a battery and then it is fully charged . then a dielectric slab of k is inserted in the capacitor while the battery is still connected SLOWLY
my question is will there be any heat produced??

my approach -- after insertion of dielectric , the charge on the capacitor increases so battery must do work and a result current must flow. so heat produced = energy produced by cell - increase in potential energy in capacitor.

my clarify **
 
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aryan pandey said:
if a capacitor is connected to a battery and then it is fully charged . then a dielectric slab of k is inserted in the capacitor while the battery is still connected SLOWLY
my question is will there be any heat produced??

my approach -- after insertion of dielectric , the charge on the capacitor increases so battery must do work and a result current must flow. so heat produced = energy produced by cell - increase in potential energy in capacitor.

my clarify **
Looks reasonable. But remember that real batteries have finite source resistance values. How does that affect your answer?
 
if i consider an ideal battery of no internal resistance then the heat will be zero
right??
 
aryan pandey said:
if i consider an ideal battery of no internal resistance then the heat will be zero
right??
I guess so. It would just take extra energy from the battery to add the extra charge.
 

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