Heat transfer -- length of the tube required to heat water....

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Discussion Overview

The discussion revolves around calculating the length of a tube required to heat water flowing through it from 20 to 40°C, with the tube wall maintained at 90°C. Participants explore the necessary equations and parameters involved in heat transfer, including mass flow rate, heat transfer coefficients, and various dimensionless numbers.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant presents the initial problem and equations but expresses uncertainty about the need for the Prandtl number and viscosity of water.
  • Another participant emphasizes the importance of calculating the Reynolds number, Prandtl number, and Nusselt number to determine the heat transfer coefficient.
  • A participant shares a derived formula for tube length, raising questions about the variables used, such as the value for temperature and the implications of varying heat transfer coefficients.
  • Multiple participants report different calculated lengths for the tube, with one stating 0.0165 m and others stating 100 m, indicating significant discrepancies in their results.
  • Concerns are raised about the validity of heat transfer assumptions when the calculated length is shorter than the diameter of the pipe.

Areas of Agreement / Disagreement

Participants express differing views on the calculated length of the tube, with some asserting a length of 0.0165 m and others arriving at 100 m. There is no consensus on the correct approach or values used in the calculations, and several participants express doubt about the validity of each other's results.

Contextual Notes

Participants highlight the need for clarity regarding the definitions of variables such as the heat load, Reynolds number, and heat transfer area. There are unresolved questions about the algebraic manipulations and assumptions made in the calculations.

Ian Limjap
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Homework Statement


Water flowing at the rate 3.5 kg s−1 through a tube with an inner diameter of 2 cm is to be heated from 20 to 40◦C. If the tube wall temperature is maintained at 90◦C, determine the length of the tube required.

Homework Equations


Q'=Cp*m*(DeltaT)
Q=2*pi*r*L*Q'

The Attempt at a Solution


Q=mass flowrate*Cp(DeltaT)
=3.5*4.18*10^3*(40-20)=292600J/s
L=Q/2*pi*rQ'
However, I'm missing Q and L.
I would like to know if I need the prandlt number for this question or the viscosity of water? Would I need more information to solve this problem?
Any help will be greatly appreciated.
Thanks.
 
Last edited:
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Yes. You need to determine the Reynolds number, the Prantdl number, and then the Nussult number. You need to determine the heat transfer coefficient. Also, you sign for the heat load is wrong.

Chet
 
Thanks for replying.
 
I ended up with L=(0.023Re^0.8Pr^0.4kA(Tw-T))/q
 
Ian Limjap said:
I ended up with L=(0.023Re^0.8Pr^0.4kA(Tw-T))/q
What value did you use for T in this equation? How could the length increase with decreasing q? How could the length increase with increasing heat transfer coefficient? Is A the wetted perimeter, the cross sectional area, or the total surface area? You need to go back and get your algebra correct.

What value do you calculate for the heat load?
What values do you calculate for the Reynolds number and the Prantdl number?
What value do you calculate for the Nussult number?
What value do you calculate for the heat transfer coefficient?
What value do you calculate for the log-mean temperature difference?
What value do you calculate for the required heat transfer area?

Chet
 
Again, thanks for replying.
 
Hi, my answer is
L=0.0165m
 
I used the mean of the bulk inlet and outlet temperatures and used that to find the properties of the fluid.
 
I apologise for the confusion I wasn't really given an answer for this.
 
  • #10
Does the required heat transfer into the fluid stream really take place in just a 16,5 mm length of 20 mm bore pipe ?
 
  • #11
Re: your message in which you ask 'what do I mean ?'

Intuitively your answer seems wrong .

In any case all the assumptions and calculation methods usually used to estimate heat transfer in pipes are going to be of very doubtful validity when used on a pipe which is actually shorter than it's diameter .
 
  • #12
Ian Limjap said:
Hi, my answer is
L=0.0165m
Now let's see the answers to the questions I asked in post #5. Nidum and I are both doubtful about what you did.
 
  • #13
I got about 100m.
 
  • #14
I did my calculations again and I ended up with 100m.
 
  • #15
Ian Limjap said:
I did my calculations again and I ended up with 100m.
I still doubt that you got it right. Until you answer my questions, I won't be responding to any more of your threads. And believe me when I say that your really need help with that other heat transfer thread you started.

Chet
 

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