Heat Transfer Reaction: CH3OH to CO + H2

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SUMMARY

The discussion centers on the heat transfer involved in the decomposition of methanol (CH3OH) into carbon monoxide (CO) and hydrogen gas (H2), with a change in enthalpy of +90.7 kJ. Participants are tasked with calculating the heat transferred when 45.0 g of CH3OH decomposes, determining the mass of hydrogen produced from a 14.0 kJ enthalpy change, and finding the heat released when 12.0 g of CO reacts with H2 to form CH2OH. The forum emphasizes the importance of showing calculations to receive assistance, adhering to the physics forum guidelines.

PREREQUISITES
  • Understanding of thermodynamics and enthalpy changes
  • Knowledge of stoichiometry in chemical reactions
  • Familiarity with the ideal gas law and molar conversions
  • Basic skills in performing heat transfer calculations
NEXT STEPS
  • Calculate heat transfer using the formula q = nΔH for the decomposition of CH3OH
  • Explore stoichiometric calculations for determining mass of products in chemical reactions
  • Investigate the heat of reaction for CO and H2 forming CH2OH
  • Review the principles of constant pressure calorimetry
USEFUL FOR

Chemistry students, chemical engineers, and anyone studying thermodynamics and reaction kinetics will benefit from this discussion.

ahappel
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Heat Transfer!

Consider the following reaction:

CH3OH(g) -> CO(g) + 2H2(g) Change in H= +90.7 kJ

(a) Calculate the amount of heat transferred when 45.0 g of CH3OH(g) are decomposed by this reaction at constant pressure. (in kJ)

(b) If the enthalpy change is 14.0 kJ, how many grams of hydrogen gas are produced? (in g)

(c) How many kilojoules of heat are released when 12.0 g of CO(g) reacts completely with H2 (g) to form CH2OH(g) at constant pressure. (in kJ)

PLEASE HELP!:confused:
 
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Sorry can't help

according to the rules in physics forum, we can't help those that didnt show their efforts. We are just guiding, not doing all the homework for you. you must at least show your way of calculations before we can help you.
 

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