squenshl Messages 468 Reaction score 4 Thread starter May 6, 2010 #1 What is H(-x)? Is it 1 if x < 0, 0 if x [tex]\geq[/tex] 0. If so what is the Fourier transform of H(-x)exp(x)?
What is H(-x)? Is it 1 if x < 0, 0 if x [tex]\geq[/tex] 0. If so what is the Fourier transform of H(-x)exp(x)?
Mute Homework Helper Messages 1,388 Reaction score 12 May 6, 2010 #2 By definition, H(x) is 0 if x < 0, 1 if x > 0, so setting x -> -x gives H(-x) is 0 if x > 0, 1 if x < 1. By inspection, you should be able to relate H(-x) to H(x), by H(-x) = 1 - H(x), which will help you with your Fourier transform.
By definition, H(x) is 0 if x < 0, 1 if x > 0, so setting x -> -x gives H(-x) is 0 if x > 0, 1 if x < 1. By inspection, you should be able to relate H(-x) to H(x), by H(-x) = 1 - H(x), which will help you with your Fourier transform.
squenshl Messages 468 Reaction score 4 May 7, 2010 #4 So is the Fourier transform of H(x)exp(-2x) + H(-x)exp(x) f(w) = 1/(2+iw) + 1/(1-iw)?