Height at which two balls collide traveling opposite direcitons

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SUMMARY

The problem involves two balls: Ball A, dropped from a height h, and Ball B, thrown upwards with an initial velocity. The key relationship established is that the velocity of Ball A is twice that of Ball B at the moment of collision. The solution reveals that the collision occurs at a height of 2/3h from the ground. The kinematic equations utilized include Vf = vi + at and xf = xi + vi*t + 1/2at^2, with g representing the acceleration due to gravity.

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Homework Statement


Ball A is dropped from the top of a building of height h at the same time that Ball B is thrown vertically upward from the ground. When the balls collide, they are moving in opposite directions, and the speed of A is twice the speed of B. At what height does the collision occur?


Homework Equations


Kinematic equations:
Vf=vi+ at
xf=xi + 1/2(vi+vf)t
xf=xi+vi*t+1/2at^2
vf^2=vi^2+2a(xf-xi)

V(ball A) = 2V(ball B)


The Attempt at a Solution



I've done kinematics equations before, but it's been a while and there is a little more involved with this one, as you're looking for the moment of impact's height where the velocity of falling ball A is twice the speed of rising ball B.

I know the velocity of ball A is simply V(Ball A) = -9.8m/s^2*t
Ball B has a velocity of V(ball B) = V-9.8m/s^2*t

The collision must occur before or at the maximum height Ball B can reach with its initial velocity, but since I can't solve for it, I'm not sure what to do.

I'm fairly sure I can set the values equal to each other because of the relationship of V(ball A) to V(ball B) but I'm having trouble conceptualizing, and don't know if they even want an exact or symbolic answer.

V(ball A) = -9.8*t
V(ball B) = (-9.8*t)/2

I need to solve for time to get height, and height to get time. But I don't have any values for velocity. The only value I have is the constant of acceleration and I feel like that isn't enough to work this out.
 
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You did the velocities well. Now you need to write equation for the height where the balls meet. They have to be at the same spot at the same time.

Use the initial velocity of B as parameter. It will cancel out. One more piece of advice: use the symbol g, do not plug in the number too early.

ehild
 
I knew that there was something I was missing out on! After solving for final height for ball a and ball b and setting them equal to each other, it came out to be a symbolic answer: 2/3h of the building. Thanks ehild! I got some good tips for conceptualizing these problems the other day, and not pluging in known values until you've solved algebraically was one of them. =)
 
Good work!:smile:

ehild
 

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