(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A ball is thrown at angle [itex]\Theta[/itex] and another ball is thrown at an angle (90-[itex]\Theta[/itex]) with the horizontal from the same point with velocity 39.2 m/s. The second ball reaches 50 m higher than the first. Find the heights.

2. Relevant equations

v = u -gt where v is the final velocity and u the initial velocity ( u = 39.2 m/s and v = 0)

S = ut - 1/2 gt^{2}

3. The attempt at a solution

Since the angles were not given, I did not find the vertical and horizontal component of velocity. I tried to find the time taken to reach the maximum height using v = u - gt and got the value as 4. I then substituted this value in the second equation and got the answer as 78.4 m. Since it says that one ball reached 50 m higher, I should either add or subtract 50 from this. Can I assume that this height is of the second ball ? Why not the first ? Even assuming that this is for the second ball, I get the answer as 28.4 and 78.4 m whereas the answer is 14.2 and 64.2.

I then attempted to solve the problem using the second equation by assuming the heights as S and S+50 with u remaining the same. However t would vary and the equation was not leading anywhere.

Where did I go wrong?

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Heights of two balls thrown at the same time

**Physics Forums | Science Articles, Homework Help, Discussion**