Heiseinberg's Microscope - Trigonometric and Interpretation questions

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Homework Help Overview

The discussion revolves around Heisenberg's microscope, focusing on the interpretation of equations related to uncertainty in position and momentum, specifically involving trigonometric functions and their implications in quantum mechanics.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to reconcile different equations related to momentum and position uncertainty, questioning the relationship between sin(2θ) and the approximations used in various sources. They seek clarification on the implications of these equations in the context of the Heisenberg Uncertainty Principle.

Discussion Status

Participants are exploring different interpretations of the equations presented, with some suggesting that the approximations may serve similar purposes despite differences. There is an ongoing inquiry into the meaning of specific terms and the implications of minimizing uncertainty in measurements.

Contextual Notes

Participants note the absence of the original problem file initially, which may have affected the clarity of the discussion. The conversation includes references to approximations and the potential difficulties in measuring both position and momentum simultaneously.

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Homework Statement


The problem along with its solution is attached as ProblemSolution.jpg.

Homework Equations


Δx = λ/sinθ (Eq. 1)
Δp_x = (h/λ)(sinε) (Eq. 2)

The Attempt at a Solution


In Wikipedia, I found this article: http://en.wikipedia.org/wiki/Heisenberg's_microscope which uses (Eq. 2) from the “Relevant equations” section above but, comparing it to my attached jpg file, ε = 2θ so I feel that the equation should become Δp_x = (h/λ)(sin(2θ)) but my jpg file states that it is Δp_x ≈ 2(h/λ)(sin(θ)) instead. Why is this the case? I even confirmed with Wolfram Alpha that sin(2θ) ≠ 2sin(θ). sin(2θ) = 2sinθcosθ but I don't see any cosθ anywhere.

Also, in the solution in the jpg file, there is the Δp_x ≈ 2h(v/c)sinθ equation; is it this equation that “[shows] that if we minimize Δx by reducing λ, this will result in a loss of information about the x-component of the elctron momentum?” If so, then what's the purpose of the Δx Δp_x product? Is the value of Δx Δp_x ≈ 4πħ = 2h supposed to be an approximation to the Heisenber Uncertainty Principle equation: Δx Δp_x ≥ ħ/2? Lastly, the last part of the solution says “We can attempt to overcome this difficulty by [ . . .].” What's the difficulty we are attempting to overcome? Is it the difficulty of measuring both the position and momentum of an electron simultaneously? Could someone please explain, confirm and/or deny these things to me even if it seems obvious to you?

If more information is needed or you want me to rephrase something, just ask.

Any input would be GREATLY appreciated!
Thanks in advance!
 

Attachments

  • ProblemSolution.jpg
    ProblemSolution.jpg
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Last edited:
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You didn't attach the file.
 
Sorry lol but, I just did now. :)
 
All of these equations, on your pdf and on wikipedia, are all approximations. Maybe they all roughly explain the same thing?
 
Last edited:
http://spiff.rit.edu/classes/phys314/lectures/heis/heis.html

This lecture thing I found when I googled Heisenberg's microscope kinda defends my angle approximation idea.

Now that I look at this lecture, I'm pretty sure they are getting that 2 from the fact that the uncertainty in p ranges from -hθ/λ to +hθ/λ?

so Δpx=2hθ/λ (or sinθ if youd like)

As far as I can tell, wikipedia and your pdf are giving different but adequate explanations of the same thing.
 
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Sorry for the late response and thank you! Those notes were also aesthetically pleasing to my eyes. :)
 

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