Helicopter accelerates while liftin what are the forces' magnitudes?

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SUMMARY

The discussion focuses on the forces acting on a 7690 kg helicopter that accelerates upward at 0.80 m/s² while lifting a 1260 kg frame. The lift force exerted by the air on the helicopter rotors is calculated using Newton's second law of motion. It is clarified that the tension in the cable connecting the frame to the helicopter is equivalent to the force that the cable exerts on the helicopter. The importance of drawing free body diagrams for both the helicopter and the frame is emphasized to analyze the net forces accurately.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Ability to draw and interpret free body diagrams
  • Knowledge of basic physics concepts such as force, mass, and acceleration
  • Familiarity with the concept of lift force in aerodynamics
NEXT STEPS
  • Calculate the lift force using the formula: Lift = Weight + (mass × acceleration)
  • Explore the relationship between tension in cables and forces in systems involving pulleys
  • Study the principles of aerodynamics related to helicopter rotor dynamics
  • Learn about the applications of Newton's second law in real-world scenarios involving multiple objects
USEFUL FOR

Physics students, aerospace engineering enthusiasts, and professionals involved in mechanical systems analysis will benefit from this discussion.

Natali
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Homework Statement


A 7690 kg helicopter accelerates upward at 0.80 m/s2 while lifting a 1260 kg frame at a construction site. (a) What is the lift force exerted by the air on the helicopter rotors? (b) What is the tension in the cable (ignore its mass) that connects the frame to the helicopter? (c) What force does the cable exert on the helicopter?


Homework Equations


Newtons laws of motion


The Attempt at a Solution


draw free body diagram for both objects. use second law of motion.
what does it mean by "helicopter rotors"? the cable gives tension but it refers to the "force the cable exerts" as something separate...
 
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helicopter rotors (blades) are just providing a lift force (through aerodynamics processes).

The tension in the cable IS the force the cable exerts on the copter.

Don't get bogged down by wording. I like here that you've mentioned drawing two diagrams. Again, the tension links them and the acceleration is not zero, but you can still use the diagrams to get expressions for Fnet... Fnet just isn't zero.
 

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