Helicopter acceleration problem

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SUMMARY

The helicopter accelerates uniformly upward from rest, and after 30 seconds, a flare is fired horizontally. The observer measures the flare's descent time to be 10 seconds. To calculate the helicopter's acceleration, use the formula for constant acceleration, which yields an acceleration of 9.8 m/s². The height from which the flare is fired can be calculated using the equation of motion, resulting in a height of 441 meters, while the helicopter's height at the moment the flare reaches the ground is 588 meters.

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Turntbull
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1. A helicopter starts from rest on the ground and starts accelerating uniformly upward. After 30 seconds a flare was fired horizontally. An observer on the ground measured the time the flare reaches the ground to be 10 seconds calculate A) acceleration of helicopter B) height flare was fired C) the height of the helicopter the instant the flare reaches the ground assuming the acceleration stays constant 2. Voy = Vo sin theta
The constant acceleration equations
3. I don't know where to start to find acceleration. I have done sin90 to try and get voy but I know that's wrong because my teacher said I'm doing it all wrong lol please help
 
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Hi Turntbull.

Can you find an expression for the time the flare takes to reach the ground after its release?
 
Turntbull said:
1. A helicopter starts from rest on the ground and starts accelerating uniformly upward. After 30 seconds a flare was fired horizontally. An observer on the ground measured the time the flare reaches the ground to be 10 seconds calculate A) acceleration of helicopter B) height flare was fired C) the height of the helicopter the instant the flare reaches the ground assuming the acceleration stays constant 2. Voy = Vo sin theta
The constant acceleration equations
3. I don't know where to start to find acceleration. I have done sin90 to try and get voy but I know that's wrong because my teacher said I'm doing it all wrong lol please help
Because the flare was fired horizontally, the time involved is the same as if an object was dropped - by dropped I mean held in an outstretched hand and released - it does not necessarily travel down immediately.
 

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