Hello forumites! I got another question (I have a lots of them, maybe I should change my textbook haha).(adsbygoogle = window.adsbygoogle || []).push({});

Suppose you have a continuous real-valued function f on the metric space X and a closed set E in X. Is f(E) closed in the reals? By definition, I know that if f(A) is closed, so is the inverse image of f(A) for a set A in X if f is continuous. But if we know that E is closed, would it be correct to say that f(E) is too?

Thanks a lot!

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# Hello forumites! I got another question (I have a lots of them, maybe

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