Help calculating work in an xy plane

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The discussion revolves around calculating work done by a force on a particle in the xy plane, specifically addressing two paths. The force is given as F = (1.9 N/m²)x²i, and participants initially struggle with applying the work formula W = F x d. Clarification is provided that the work done is calculated using the dot product of the force and displacement vectors, leading to confusion about the final speed of the particle. The correct approach for part (b) involves integrating the force over the displacement. Ultimately, participants confirm that the work done is expressed in Joules, while the final speed is a separate consideration.
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Homework Statement


A force
Farrowbolditalic.gif
= (1.9 N/m2)x2i is applied to a particle initially at rest in the xy plane. Find the work done by this force on the particle and the final speed of the particle as it moves along a path as follows. The given force is the only force doing work on the particle.

a) in a straight line from point (2.1 m, 2.1 m) to point (2.1 m, 7.5 m)
_________ J

b) in a straight line from point (2.1 m, 2.1 m) to point (4.8 m, 6.6 m)
__________ J

Homework Equations


W = F x d

The Attempt at a Solution


a) Due to the equation that I found above, I have used the distance formula to calculate d:
= 5.4
Then I did F x d = 1.9 * 5.4 = 10.26 (Wrong)

b) Same this as above:
= 2.7
F x d = 1.9 * 2.7 = 5.13 (Wrong)
-------------------------------------------------
On top of these incorrect attempts, I am also confused with what the problem is asking... It says to find the word done by the force, and the final speed of the particle, but the answer boxes contain a J for Joules which is a unit of work. How would I put work and speed in one box?
 
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Is the correct statement of the force F = 1.9 x2 i Newtons?
(where i is the unit vector in the x direction.)

PS it does not say to find the final speed. Both answers will be in Joules.
 
Yes that is the correct statement, sorry about that. I have corrected it.

It does say in the question "Find the work done by this force on the particle and the final speed of the particle as it moves along a path as follows", but it looks like the questions are asking for work, so I guess I'll just ignore that part.
 
Force and displacement are vectors. What, exactly, is the formula for the work done in terms of those vectors?
 
Oh! It looks like it's the dot product of the force and the displacement vector.

EDIT: Okay, I got a) correct: W = F dot d = 0 + 0 = 0
Now for b) I get 5.13x2 and it is wrong. I think it might have something to do with the x
 
Last edited:
Shadow236 said:
Oh! It looks like it's the dot product of the force and the displacement vector.

EDIT: Okay, I got a) correct: W = F dot d = 0 + 0 = 0
Now for b) I get 5.13x2 and it is wrong. I think it might have something to do with the x

You have to integrate F dot dx to get part (b).
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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