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Work of a Particle in the XY Plane

  1. Nov 9, 2014 #1
    1. The problem statement, all variables and given/known data
    A force acting on a particle moving in the xy-plane is F = (2yi + 1.2x^2 j)N. where x and y are in meters. The particle moves from the origin to a final position having coordinates x = 5m and y = 5m. Calculate the work done by F along OAC

    2. Relevant equations
    Integral of force by distance
    W = ∫(Fxdx + Fydy)

    3. The attempt at a solution
    I have the answer. And I know what they did. But what I don't understand is how it makes sense.
    The solution involves breaking up the integral into two partitions, Woa and Wac.
    This is what I don't really understand - how is the work on OA zero? There is a force acting in the x direction and it moves from O to A. So by definition, since there is a force acting over a distance there should be work right? (Unless I'm not reading this properly)
     
  2. jcsd
  3. Nov 9, 2014 #2

    ehild

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    Where are points A and C?
     
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