Calculus Problem Help: Tangent Line & Demand Curve Calculation

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To find the equation of the tangent line for f(x) = (x - 6)^8 at x = 7, the derivative must be calculated first. The demand curve is defined as q = f(p) = 5,000e^(-0.30p), and to find f(6) and f'(6), the values need to be computed using differentiation. Participants emphasize the importance of showing work for assistance and caution against relying on others to complete homework. Overall, the discussion highlights the necessity of understanding calculus concepts rather than seeking direct answers.
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help!Calculus problems

1)Find the equation of the tangent line to f(x) = (x - 6)8 at the point where x = 7.




2)The demand curve for a product is given by
q = f(p) = 5,000e-0.30p,
where q is the quantity sold and p is the price of the product, in dollars. Find f(6) and f'(6).
 
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I have a hunch that maybe you did not write the problem correctly.
 
Also, nobody is going to do your homework for you, so you have to put your work down if you want help.
 
u probably got the question wrong the given equation is linear. tangent at any point of linear equation is that line itself. plus u'll never learn if r going to have someone else do ur HW.
 
I suspect that the first problem involved (x-6)8.

However, there is no work shown so don't expect anyone to do your work for you.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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