Help elastic collistion, cons of momentum problem

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The discussion focuses on calculating the final velocities of two blocks after a perfectly elastic collision. Block 1, with an initial speed of 10 m/s, collides with Block 2, which has twice the mass and an initial speed of 5 m/s. The conservation of momentum and kinetic energy principles are applied, leading to the equation v1 + 2v2 = 20, where v1 and v2 represent the final velocities of Block 1 and Block 2, respectively. The multiplication of Block 2's velocity by two is due to its greater mass, and the mass terms cancel out in the momentum equation.

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nchin
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Block 1 moves with speed of 10m/s to right. It hits block 2 which has twice the mass of block 1 and speed of 5m/s to right. compute the magnitude and direction of block 1 for a perfectly elastic collision.

solution:

u1 = 10m/s
u2 = 5m/s

m1v1 + m2v2 = m1u1 + m2u2 ---->
v1 + 2v2 = u1 + 2u2
...= 10 + 2(5) = 20

(1) v1 + 2v2 = 20

why did u2 and v2 get multiplied by two and why did the m cross out?
 
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nchin said:
why did u2 and v2 get multiplied by two and why did the m cross out?
Are you saying you've just copied these steps from somewhere else and don't know the logic behind them? If those steps were your own work, surely you know why you made them.
 

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