Help Find C(x,y) for Triangle A(0,0) AB=4 BC=3 AC=5

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Discussion Overview

The discussion revolves around finding the coordinates of point C in a triangle defined by points A(0,0) and the lengths of the sides AB=4, BC=3, and AC=5. The context includes geometric reasoning and the properties of triangles.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant states the lengths of the sides and the direction of line BC, suggesting it goes into the third quadrant.
  • Another participant identifies the triangle as a 3,4,5 triangle and implies that this may help in determining the angle at point B.
  • A participant proposes that the angle at B is 200 degrees without providing a calculation or reasoning for this value.
  • Another participant requests clarification on how the angle of 200 degrees was calculated.

Areas of Agreement / Disagreement

There is no consensus on the angle at B, as one participant suggests it is 200 degrees while another asks for the reasoning behind this calculation. The discussion remains unresolved regarding the determination of point C.

Contextual Notes

The discussion does not clarify the assumptions regarding the triangle's orientation or the coordinate system being used, which may affect the interpretation of the angle and the position of point C.

tukilala
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A(0,0)
and i know that AB=4 BC=3 AC =5
BC goes diagonally downward into the direction of the third "quadrant".

how can i find C(x,y) ? thnx
 
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Welcome to PF!

tukilala said:
A(0,0)
and i know that AB=4 BC=3 AC =5
BC goes diagonally downward into the direction of the third "quadrant".

how can i find C(x,y) ? thnx

Hi tukilala! Welcome to PF! :smile:

Well, for a start, it's a 3,4,5 triangle …

so the angle at B is … ? :wink:
 


200 degrees
 
tukilala said:
200 degrees

show us how you calculated that :wink:
 

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