Help Finding Values of Cosx & Sinx | tanx=2

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Mathslova
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Can someone kindly help to find the exact values of cosx and sinx when tanx=2..:redface:
 
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well i could have done it easily if it was in half angle form..i.e tan(1/2x)=2...i have some formulae to use but for that one i have no idea how to start
 
You don't really need a formula as such. Try drawing a diagram (i.e. a right angled triangle). You know the value of the tangent of one angle, so you should be able to write down the values of two of the sides. There's a theorem that you know to find the third side-- try using this.
 
Well, the simplest way is to utilize the identity:
[tex]\tan^{2}(x)+1=\frac{1}{\cos^{2}(x)}[/tex]
If you are not familiar with that result, you should try to prove it first.
 
cristo said:
You don't really need a formula as such. Try drawing a diagram (i.e. a right angled triangle). You know the value of the tangent of one angle, so you should be able to write down the values of two of the sides. There's a theorem that you know to find the third side-- try using this.

Very much appreciated...I used SOHCAHTOA and got the answer I was looking for:smile:
 
robphy said:
In what kind of problem might the expression tan x=2 occur?

robphy said:
Ideally, the OP would have used my hint.

I understand your point, but I can think of many problems involving tan x= 2 (or other values of tan x) that have nothing to do with right triangles.