Help Finding Velocity Needed for Object in Moon's Orbit

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SUMMARY

The discussion focuses on calculating the velocity required for an object to maintain a stable orbit around the Moon. Key equations include the gravitational force formula, F_g = GMm/r², and the centripetal force equation, which leads to the conclusion that the mass of the orbiting object cancels out. The derived formula for orbital velocity is v = √(GM/r), indicating that the required velocity is independent of the object's mass. The conversation emphasizes that the object does not need to reach escape velocity to remain in orbit.

PREREQUISITES
  • Understanding of gravitational force equations, specifically F_g = GMm/r²
  • Knowledge of centripetal motion and its relationship to orbital mechanics
  • Familiarity with the concept of escape velocity
  • Basic algebra and square root calculations
NEXT STEPS
  • Research the derivation of the orbital velocity formula v = √(GM/r)
  • Study the differences between escape velocity and orbital velocity
  • Explore the implications of circular motion in gravitational fields
  • Learn about the effects of varying mass on orbital dynamics
USEFUL FOR

Astronomy students, physicists, and engineers interested in orbital mechanics and gravitational physics will benefit from this discussion.

jeffreydim
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hello,
find velocity required to keep an object in moon's orbit? so far, a = velocity squared over radius and force equals g constant times mass 1 times mass 2 over radius squared, but the object's mass is not given and mass of moon can be found, any help?
 
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HINT: You already know that:

F_g = \frac{GMm}{r^2}

But what else is this equal to. What kind of motion is the object in if it is in orbit? You should be able to set the above expression equal to another expression involving m, then the m's should cancel. See how far you can now. Good Luck.
 
The thing is, it is independent of mass of the object. This is essentially what Galileo demonstrated nearly 400 years ago.
 
Calculate escape velocity, cancelling the m would result from setting it equal to 1/2*mv^2, now v = sqr(GM/r), and the orbit needs to be less than this. interesting stuff...
 
Sorry, escape velocity is going a bit too far, literally and figuratively. You do not need to be at escape velocity to remain in orbit, because that is partly what escape velocities are, the object will be able to escape from the gravitaional influnce of the moon.

Try in an orbit, we assume it is in circular motion. Think of what equations you need to apply.
 

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