Help finding velocity using data table

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Homework Help Overview

The discussion revolves around creating a time-velocity data table using provided position data at specific time intervals. The subject area is kinematics, focusing on the calculation of velocity from position data.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss which data points to use for calculating velocity at specific times, particularly at 0.25 seconds. There is confusion regarding the difference between average velocity and instantaneous velocity, leading to questions about the appropriateness of selected data points.

Discussion Status

Participants are exploring different interpretations of how to calculate velocity using the data points. Some guidance has been offered regarding the use of slopes between endpoints, but there remains uncertainty about calculating exact velocities at specific moments.

Contextual Notes

There is an acknowledgment that the available data points may limit the ability to determine exact velocities, leading to discussions about approximations and interpolation between values.

terasnap
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Homework Statement



Using the data found, in this chart, create a time-velocity data table.

Time(s),Position(m)[down]: (0,0), (0.25,0.29), (0.50,1.15)


Homework Equations



v= change in position/change in time

The Attempt at a Solution



I'm just wondering which sets of data points I should be using to calculate the velocity at 0.25 seconds: for example v=(0.25-0)/(0.29-0) is different from v=(0.50-0.25)/(1.15-0.29).
 
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Since the graph is linear between endpoints, select the points and compute the slope of the line, using the velocity equation you indicated and the endpoints of the line. Do the same for the second line, and you obtain the velocities.
 
NasuSama said:
Since the graph is linear between endpoints, select the points and compute the slope of the line, using the velocity equation you indicated and the endpoints of the line. Do the same for the second line, and you obtain the velocities.

Sorry, but I don't really understand how to find the exact velocity at 0.25 seconds, since your method calculates the average velocity between 0s-0.25s.
 
terasnap said:

Homework Statement



Using the data found, in this chart, create a time-velocity data table.

Time(s),Position(m)[down]: (0,0), (0.25,0.29), (0.50,1.15)


Homework Equations



v= change in position/change in time

The Attempt at a Solution



I'm just wondering which sets of data points I should be using to calculate the velocity at 0.25 seconds: for example v=(0.25-0)/(0.29-0) is different from v=(0.50-0.25)/(1.15-0.29).
You would use v=(0.29-0)/(0.25-0) to get your best approximation to the velocity at 0.125, and you would use v=(1.15-0.29)/(0.5-0.25) to get your best approximation to the velocity at 0.375.
 
terasnap said:
Sorry, but I don't really understand how to find the exact velocity at 0.25 seconds, since your method calculates the average velocity between 0s-0.25s.
Hi terasnap, welcome to Physics Forums.

There is no way to calculate the "exact" velocity at any moment, when all you have are a few data points. It is reasonable to assume that speed changes smoothly, so the data points you have should give their best approximation to the speed at those times midway between your data values. Calculate these values of velocity, and you can then use these figures to interpolate intermediate values of velocity.

Chestermiller has shown you the way to begin.
 

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