HELP Friction on Ice involving weight

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SUMMARY

The discussion focuses on calculating the coefficient of kinetic friction for a car weighing 2580.0 kg that skids to a stop over a distance of 26.4 m while traveling at a speed of 14.0 m/s. The user correctly identifies the need to find the acceleration, which is calculated as -0.5303 m/s². The relationship between acceleration and friction is established through the formula a/g = μ, where μ represents the coefficient of kinetic friction, and g is the acceleration due to gravity.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concepts of friction and its coefficients
  • Basic algebra for solving equations
  • Knowledge of kinematic equations
NEXT STEPS
  • Study the derivation of the friction formula F_friction = μW
  • Learn about kinematic equations and their applications in motion analysis
  • Explore online resources for physics equations, such as HyperPhysics
  • Investigate real-world applications of friction in automotive safety
USEFUL FOR

Students studying physics, automotive engineers, and anyone interested in understanding the dynamics of vehicle motion on slippery surfaces.

imadagron89
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You are driving a 2580.0 kg car at a constant speed of 14.0 m/s along an icy, but straight, level road. As you approach an intersection, the traffic light turns red. You slam on the brakes. Your wheels lock, the tires begin skidding, and the car slides to a halt in a distance of 26.4 m. What is the coefficient of kinetic friction between your tires and the icy road.



The Attempt at a Solution


I found the acceleration to be -.5303 by taking -14/26.4 (v=v0+at) but now I'm confused as how to find the kinetic friction by stopping
 
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Find the acceleration or deceleration, then

a/g = \mu, since Ffriction = ma = \mu W = \mumg.
 
im sorry man still not getting it, is there some sort of website that has all the equations on it?
 

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