HELP, how do i integrate (x)^1/3

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Discussion Overview

The discussion revolves around the integration of the function \( (x)^{1/3} \). Participants are seeking assistance with the integration process, exploring different approaches and interpretations of the integral.

Discussion Character

  • Homework-related, Mathematical reasoning

Main Points Raised

  • One participant requests urgent help with integrating \( (x)^{1/3} \).
  • Another participant suggests that the integral can be expressed as \( \frac{x^{-2/3}}{3} \), also noting it can be written as \( \frac{1}{3x^{2/3}} \).
  • A different participant draws a parallel between integrating \( (x)^{1/3} \) and integrating \( (x)^{1} \), proposing that rewriting \( (x)^{1} \) as \( (x)^{3/3} \) might clarify the integration process.
  • One participant reiterates the integration formula for powers of \( x \), stating that for all \( \alpha \in \mathbb{R} \) except -1, the integral is given by \( \int x^{\alpha} dx = \frac{x^{\alpha + 1}}{\alpha + 1} + C \).
  • A later reply corrects an earlier statement, indicating that the integral should result in \( \frac{3x^{4/3}}{4} \).

Areas of Agreement / Disagreement

There appears to be some confusion regarding the integration process, with multiple participants providing different expressions for the integral. The discussion does not reach a consensus on the correct form of the integral.

Contextual Notes

Participants express uncertainty about the integration steps and the application of the integration formula, indicating a need for clarity on the assumptions involved in the integration process.

butoyzki
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HELP, URGENT! how do i integrate (x)^1/3

how do i solve this?
please help me integrate (X)^1/3
 
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x^(-2/3) / 3

aka..
1 over 3x^(2/3)
 
The same way you would integrate X^1.

If I were to write X^1 as X^(3/3), would this help you see the similarity? How would you integrate X^(3/3)?
 
okevino said:
x^(-2/3) / 3

aka..
1 over 3x^(2/3)
Errr, well, it's integration, not differentiation. :rolleyes:

For all \alpha \in \mathbb{R}, not -1. We have:
\int x ^ {\alpha} dx = \frac{x ^ {\alpha + 1}}{\alpha + 1} + C

:)
 
opps..
then it's

3x^(4/3) over 4
 

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