Help: Lawn Mowing Question Physics related

  • Thread starter Thread starter NegaChin
  • Start date Start date
  • Tags Tags
    Physics
Click For Summary
SUMMARY

The discussion focuses on calculating forces related to an 18.0 kg lawn mower being pushed at a constant speed with a force of 71.0 N at an angle of 43.0° to the horizontal. The horizontal retarding force is calculated to be 51.9 N, and the normal force exerted by the ground is 225 N. To accelerate the mower from rest to 1.6 m/s in 2.0 seconds, participants are guided to first determine the required acceleration and then calculate the net force needed, accounting for the existing retarding force.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of free-body diagrams
  • Familiarity with kinematic equations
  • Ability to calculate forces using vector components
NEXT STEPS
  • Learn how to draw and interpret free-body diagrams for complex systems
  • Study kinematic equations, particularly for acceleration and velocity
  • Explore the concept of net force and its application in real-world scenarios
  • Investigate the relationship between applied forces and retarding forces in physics problems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of force calculations in real-life applications.

NegaChin
Messages
13
Reaction score
0
A person pushes a 18.0 kg lawn mower at constant speed with a force of 71.0 N directed along the handle, which is at an angle of = 43.0° to the horizontal .

(a) Draw the free-body diagram showing all forces acting on the mower. (Do this on paper. Your instructor may ask you to turn in this diagram.)
(b) Calculate the horizontal retarding force on the mower
N
(c) Calculate the normal force exerted vertically upward on the mower by the ground.
N
(d) Calculate the force the person must exert on the lawn mower to accelerate it from rest to 1.6 m/s in 2.0 seconds (assuming the same retarding force).

i found b,c, just a little confused on which to start d
b is 51.9 N
c is 225 N

there is a picture if it helps
Please help soon!
 

Attachments

  • 4_40alt.gif
    4_40alt.gif
    36.5 KB · Views: 951
Physics news on Phys.org
Hello,

For part (d), you need to calculate the force that would need to be applied to the handle to accelerate the lawnmower.

The original force of 71N was not enought to accelerate the lawnmower, it was just enough to keep it at a constant speed. Can you find the acceleration required to go from rest to 1.6 m/s in 2.0 seconds? If you can, then you can find the force that would need to be applied to generate this acceleration-- but you have to remember that there is already a force acting against this one, that you will need to overcome.

What I'm trying to say (and I think I'm botching it a bit) is that if you can find the net acceleration you need, you can then find the net force you need, and from there subtract out the retarding force, leaving you only with the force you need to apply. Of course, you're going to have the same sin/cos trickery, because you have to apply the force on the handle.

Hope this helps, let me know if you need more clarification. Personally, I don't like problems like this, because there's typically no physical reason to assume a retarding force would be equal (in this case) at different applied forces-- they typically vary according to the applied force. But in this case, they're saying to assume the same, to make the problem easier... but this goes against one's physical intuition. Bah.
 
yes can u clarify a bit more
 
Start with this:

v = v_0 + at

and then use this:

\sum{F} = ma_{net} \Rightarrow \frac{F_{retarding} + F_{applied}}{m} = a_{net}

Where, for this problem, we're only concerned with the accelerations, velocities, and everything else, in the x direction.

They've given you what you need to find the net acceleration, that will produce an increase in velocity from 0 to 1.6 m/s in 2.0s. You can then use this acceleration, and the one force you do know, to find the other force you don't know.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
Replies
6
Views
6K
Replies
2
Views
2K
  • · Replies 18 ·
Replies
18
Views
13K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 6 ·
Replies
6
Views
7K
  • · Replies 4 ·
Replies
4
Views
21K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
1
Views
5K