Help Maximizing Range of Projectile Motion

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Homework Help Overview

The discussion revolves around maximizing the range of a projectile, specifically in the context of a trebuchet with a given release speed and height difference. The original poster is tasked with calculating the range for various angles and determining the optimal angle for maximum distance.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster seeks guidance on formulas or techniques to determine the best angle for maximum range. They question the applicability of a specific formula they found and clarify the meaning of their height difference value in relation to the problem context.

Discussion Status

Participants are exploring different aspects of the problem, including the application of kinematic equations and the interpretation of variables. Some participants provide insights into the physics principles involved, while others express confusion about the terminology used. There is no explicit consensus on the best approach yet, but various lines of reasoning are being discussed.

Contextual Notes

The original poster is working under specific constraints, including a requirement for high accuracy and a defined height difference related to the projectile's target. There is also a mention of the educational level, which may influence the complexity of the discussion.

Rowah
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My teacher gave me a project that requires us to find the angle that "produces the maximum range for a trebuchet with a release speed of 50 m/s."

My (Delta)h value is +46 and I have to calculate the range produced by 5 different angles, graph it, and find the best angle to a hundredth of a degree. I'm going to calculate for the angles 5, 25, 45, 65 and 85.

My Questions:

1) Are there any formulae or techniques that would allow me to figure out the best angle in advance? I know my teacher is a perfectionist and DEMANDS absolute accuracy! Would this formula work? I used it and got a value of 51.3542 degrees. http://scitation.aip.org/servlet/GetImg?key=PHTEAH000043000002000098000001%3A0%3A2%3A28&t=a&d=a

2) My (delta)h value is +46, my teacher said "it would apply to a group trying to target a castle 50 meters above them." Does that mean (delta)y is equal to +46?

Thanks in Advance ^_^
 
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ok logically you can deduce the answer but its better to work it out this way a.) because youll understand it better and b.) because youll get marks for working

you know Newtons laws of motion
ok logically you can deduce the answer but its better to work it out this way a.) because youll understand it better and b.) because youll get marks for working

Newtons laws of motion tell you:
[tex]s = ut + (1/2)a{t^2}[/tex]

You can, from your information, work out the component (vertical and horizontal) form of your velocity. From the above equations you work out when the projectile will hit the ground solving for time (be careful, this produces a quadratic, think what the other solution might be!) when you have this time constant you multiply by your horizontal component to get max distance.

hope this helps
-G
 
Sorry, I'm only in Grade 12 physics, I don't understand >_<

I have no idea what "s" and "u" are.
 
Last edited:
FunkyDwarf said:
...Newtons laws of motion tell you:
[tex]s = ut + (1/2)a{t^2}[/tex]...

This equation doesn't have anything to do with Newtons law of motion, which are a part of dynamics, and not kinematics.

's' represents displacement, and 'u' represents velocity.
 
ok fair point, its not from Newtons laws but he derived them when he basicallyt made up calculus (which made the universe more complicated and school harder :) )

but at the year 12 level those equations should be common place
 
Cool, I finished the assignment, thanks guys :D
 

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