Help Me Calculate How high SuperMan can Jump

  • Thread starter Thread starter theoblivin8r
  • Start date Start date
  • Tags Tags
    Jump Superman
Click For Summary
SUMMARY

The discussion focuses on calculating the maximum height Superman can jump based on his initial velocity and angle of takeoff. Given Superman's mass of 100 kg and an initial vertical velocity of 180.99 m/s at an angle of 86.9 degrees, the key equations for projectile motion are applied. The final vertical velocity at the peak of the jump is zero, allowing for the use of kinematic equations to determine the height. The participant also notes the irrelevance of horizontal velocity in this specific calculation.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with kinematic equations
  • Basic knowledge of energy conservation concepts
  • Ability to perform vector decomposition of velocities
NEXT STEPS
  • Study the kinematic equation for vertical motion in detail
  • Learn about energy conservation in projectile motion
  • Explore vector decomposition techniques for velocity calculations
  • Practice solving similar physics problems involving projectile motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and projectile motion, as well as educators looking for practical examples to illustrate these concepts.

theoblivin8r
Messages
9
Reaction score
0

Homework Statement


This is a semester review. I am having trouble starting the second part of this question. It is well-know fact that Superman is "faster than a speeding bullet, more powerful than a locomotive, and able to leap tall buildings in a single bound." Assume his mass is 100kg.

The first part we are given his initial velocity as 181 m/s. That is one meter faster than a characteristic bullet. His jump takes off at a 86.9 degree angle. What are his initial velocities in the x and y direction. No trouble here.

V(xinitial)=1.26 m/s
V(yinitial)=180.99 m/s

The second part asks how tall of a building can he leap using the above data.

Homework Equations


Y=Yinitial)+V(yinitial)(time)+1/2Ay*(time^2)

V(yfinal)^2=V(yinitial)^2+Ay(X-Xinital)

V(yfinal)=V(yinitial)+Ay*Time

The Attempt at a Solution


I have his initial velocities in the x and y direction. I am confused on how to solve for a final velocity without knowing time or the final velocity in the y direction. I am thinking that since I have two unknowns I might have to rearrange and equation and substitute it into another one to solve for one unknown. Any help is greatly appreciated!
 
Physics news on Phys.org
Here's a hint: when superman is at the highest point in his jump, his vertical velocity (let's call this his "y velocity") is zero. (He starts with a positive y velocity, and if his y velocity were positive at the peak of his jump, he'd keep going up--so it wouldn't be the peak of his jump). So you can use V_y=0 for your final velocity. The horizontal or x velocity doesn't really matter in this problem, since it stays constant throughout. Honestly, including a small x velocity in this problem is probably just meant to confuse you.

However, I think there's an easier way to solve this problem. Use kinetic and potential energies.
 
Thanks for the hint. I had missed that key information. I have to solve this using projectile motion and not energy so thanks anyway. I'll post questions if I have anymore.
 
When the super man reaches the highest point of the building, his Vy(final) can be taken as zero.
 

Similar threads

  • · Replies 26 ·
Replies
26
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
19
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
3
Views
2K
Replies
13
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 16 ·
Replies
16
Views
17K
  • · Replies 5 ·
Replies
5
Views
4K