1. The problem statement, all variables and given/known data Kit the cat is going to jump through a hoop. He begins on a wicker cabinet at a height of 1.745 m above the floor and jumps through the center of a vertical hoop, reaching a peak height 3.115 m above the floor. With what initial velocity did Kit leave the cabinet if the hoop is at a horizontal distance of 1.567 m from the cabinet? (Express your answer in vector form) 2. Relevant equations X (or Y) = vit + 1/2at2 Vf2 = Vi2 + 2a(x2-x1) And possibly quadratic equation. 3. The attempt at a solution I was able to calculate the initial velocity of the y direction using Vf2 = Vi2 + 2a(x2-x1) (I know because the cat reaches peak height at 0, the vertical velocity at that time was 0).From there, I tried to solve for t. I know once I get t, I can find the initial velocity of x, but I came to an error in what I believe is my t. I tried plugging into Y = vit + 1/2at2 and made it into the quadratic formula, but got two positive answers 0.54739930925614 s and 0.51076395604999 s. Then I tried the Vf = Vi + at and got .529 s. What can I do to find time, correctly?