Help me find the anitderivative of this

Main Question or Discussion Point

What is the antiderivative of tanx/sec^99x?

Vid
tan(x) = sin(x)/cos(x)
1/sec(x) = cos(x)

tan(x)/sec^99(x) =...?

A simple u-sub should pop right out once you simplify this.

benorin
Homework Helper
Make the substitution $$u=\sec x$$