What is the antiderivative of tanx/sec^99x?
May 28, 2008 #2 Vid 402 0 tan(x) = sin(x)/cos(x) 1/sec(x) = cos(x) tan(x)/sec^99(x) =...? A simple u-sub should pop right out once you simplify this.
tan(x) = sin(x)/cos(x) 1/sec(x) = cos(x) tan(x)/sec^99(x) =...? A simple u-sub should pop right out once you simplify this.
May 28, 2008 #3 benorin Homework Helper Insights Author 1,443 184 Make the substitution [tex]u=\sec x[/tex]