What is the antiderivative of tanx/sec^99x?
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May 28, 2008 #2 Vid 401 0 tan(x) = sin(x)/cos(x) 1/sec(x) = cos(x) tan(x)/sec^99(x) =...? A simple u-sub should pop right out once you simplify this.
tan(x) = sin(x)/cos(x) 1/sec(x) = cos(x) tan(x)/sec^99(x) =...? A simple u-sub should pop right out once you simplify this.
May 28, 2008 #3 benorin Homework Helper Insights Author Gold Member 1,293 98 Make the substitution [tex]u=\sec x[/tex]