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Help me find the anitderivative of this

  1. May 27, 2008 #1
    What is the antiderivative of tanx/sec^99x?
     
  2. jcsd
  3. May 28, 2008 #2

    Vid

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    tan(x) = sin(x)/cos(x)
    1/sec(x) = cos(x)

    tan(x)/sec^99(x) =...?

    A simple u-sub should pop right out once you simplify this.
     
  4. May 28, 2008 #3

    benorin

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    Homework Helper

    Make the substitution [tex]u=\sec x[/tex]
     
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