Help me find the anitderivative of this

[moela]

What is the antiderivative of tanx/sec^99x?

 

[Vid]

tan(x) = sin(x)/cos(x)
1/sec(x) = cos(x)

tan(x)/sec^99(x) =...?

A simple u-sub should pop right out once you simplify this.

 

[benorin]

Make the substitution $$u=\sec x$$