moela Messages 6 Reaction score 0 Thread starter May 27, 2008 #1 What is the antiderivative of tanx/sec^99x?
Vid Messages 401 Reaction score 0 May 28, 2008 #2 tan(x) = sin(x)/cos(x) 1/sec(x) = cos(x) tan(x)/sec^99(x) =...? A simple u-sub should pop right out once you simplify this.
tan(x) = sin(x)/cos(x) 1/sec(x) = cos(x) tan(x)/sec^99(x) =...? A simple u-sub should pop right out once you simplify this.
benorin Science Advisor Insights Author Messages 1,442 Reaction score 191 May 28, 2008 #3 Make the substitution [tex]u=\sec x[/tex]