Help me find the anitderivative of this

  • Thread starter moela
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  • #1
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What is the antiderivative of tanx/sec^99x?
 

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  • #2
Vid
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tan(x) = sin(x)/cos(x)
1/sec(x) = cos(x)

tan(x)/sec^99(x) =...?

A simple u-sub should pop right out once you simplify this.
 
  • #3
benorin
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Make the substitution [tex]u=\sec x[/tex]
 

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