HELP:moment of inertia/angular momentum

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The discussion centers on calculating the angular momentum of a solid ball with a radius of 0.4 meters and density of 1.7 kg/m³, rolling at 11.1 m/s. Initial calculations yield an angular momentum of 0.809 Joule-seconds, but the correct answer is 2.83 Joule-seconds when considering the axis of rotation at the contact point with the plane. The formula for moment of inertia must include both the ball's rotation and translation, specifically using I=(2/5)MR² + MR². Additionally, the validity of the problem is questioned, as angular momentum should be defined relative to a specific point. The discussion emphasizes the importance of clearly defined parameters in physics problems.
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A solid ball of radius 0.4 meters, made from a material of density 1.7 kG/cubic meter, rolls along a rough horizontal plane with a speed of 11.1 meters/sec. What is its angular momentum (in Joule.secs)?

density = mass/volume and volume of a sphere = (4/3)(pi)(r)^3
so the mass is 0.4557kg

I=(2/5)MR^2 ---> (2/5)*0.4557*(0.4)^2 = 0.02917

w=v/r ---> 11.1/0.4 = 27.75
L=Iw ---> 0.02917*27.75 = 0.809

Student response 0.809
Correct answer 2.83
 
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You have to change the axis of rotation to the contact point of the ball with the plane. It's 2/5mr^2 + mr^2. This will give you the correct answer.
 
"A solid ball of radius 0.4 meters, made from a material of density 1.7 kG/cubic meter, rolls along a rough horizontal plane with a speed of 11.1 meters/sec. What is its angular momentum (in Joule.secs)?"

Cartoonkid has given you the approah they're probably after.
However, as it stands, this question is completely meaningless.
Angular momentum is computed RESPECTIVE to a point. If you haven't been given that, then the exercise is flawed.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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