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## Homework Statement

A tree is being transported on a flatbed trailer by a landscaper. If the base of the tree slides on the trailer, the tree will fall over and be damaged. If the coefficient of static friction between the trailer and the tree is 0.5, what is the minimum stopping distance of the truck, travelling at 15. 278 m/s, if it is to accelerate uniformly and do not have the tree slide forward and fall on the trailer?

Mu s= 0.5

V1= 15.278 m/s

d=?

## Homework Equations

I'm not sure but i think

v2^2=v1^2+2ad

Us= Ffs/Fn

f=ma

v=d/t

## The Attempt at a Solution

i don't really know what to do since i wasn't given the mass so i cant find acceleration or normal force[/B]

0.5(9.8)= 4.9

a= -4.9 m/s^2

v2^2-v1^2/2a=d

0^2-15.278^2?29-4.9)

d= 23.8 m