1. The problem statement, all variables and given/known data Two blocks are connected over a pulley. The mass of block A is 10 kg, and the coefficient of kinetic friction between A and the incline is 0.20. Angle theta of the incline is 30 degrees. Block A slides down the incline at constant speed. What is the mass of Block B? 2. Relevant equations a = Fnet/m fk = [coefficient of kinetic friction] * N Fg = mg 3. The attempt at a solution I found N [normal force] to equal 84.87 N and fk to equal 16.97 N, but those could be wrong. Also, when tilting the plane, Fgx equals 49 N and a = 0. I don't know if those are correct, because I started to get confused at the end. My answer is 3.27 kg (after getting a weight of 32.03 N). I doubt that's the right answer because I started to mix up which forces should be equal to each other. Unfortunately I can't find the image of the diagram online, but Block A is on an incline in this direction / with the angle 30 degrees above the horizontal on the positive x axis. the pulley is attached to the top right corner (at the highest point) and Block B is hanging vertical. It is SIMILAR to this picture, except block a is on the incline sliding downward and block b is hanging vertically, I assume being pulled upward. I need help tonight!