Help Needed: Understanding An=1x3x5... (2n-1)/(2n)^n Convergence

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SUMMARY

The sequence An = (1x3x5... (2n-1))/(2n)^n converges to 0. The convergence is established by distributing the denominator (2n)^n across each factor in the numerator, resulting in terms like (1/2n)(3/2n)(5/2n)...(2n-1)/2n. As n increases, each factor becomes less than 1, leading to a product that approaches 0. This analysis confirms the convergence behavior of the sequence.

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I'm trying to figure out the following:

An=1x3x5... (2n-1)/(2n)^n and I'm trying to determine if it converges or diverges and if it converges, what the limit is. The answer is 1/2n x 3/2n x 5/2n... (2n-1)/2n and it converges, but I don't understand what they did or how they got to the answer. Any help?
 
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anderma8 said:
I'm trying to figure out the following:

An={1x3x5... (2n-1)}/(2n)^n and I'm trying to determine if it converges or diverges and if it converges, what the limit is. The answer is 1/2n x 3/2n x 5/2n... (2n-1)/2n and it converges, but I don't understand what they did or how they got to the answer. Any help?
Your "answer" does not give the limit. What they have done, very simply, is take that (2n)^n in the denominator and distribute it to each of the factors in the numerator. For example, if n= 3 you have {1*3*5}/(6^3)= (1/6)(3/6)(5/6). Since each factor is less than 1, and multiplying any positive number by a number less than one gives a smaller product, multiplying by more and more such fractions makes the product smaller and smaller- the sequence clearly converges to 0.
 

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