Help needed with calculating distances from circles

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The discussion focuses on calculating distances between circles on linear tapered strips using a 1-inch round cutter. The circles must connect at half the section depth along the strip, requiring closer placement as the strip narrows. A suggested method involves fixing the first circle and calculating subsequent distances iteratively based on angles and known slopes. The distance between circles is derived using trigonometric relationships, specifically involving cosine functions. The process is acknowledged as potentially tedious, inviting further suggestions for more efficient solutions.
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I'm looking to find someone who can help me with my problem...

My problem is that I need to remove material from linear tapered strips with a 1 inch round cutter. The circles need to connect to each other at half the section depth over the entire length of the strip

--->

http://www.keone.com/hollow.gif


Because the diameter of the strips decreases the circles need to be placed closer to eatchother so that the circles keep connecting eatchother at the hart of the strip.

My problem is how to calculate the distances...

Can someone please help me out with this?

The picture in the link will make it more clear

Thanks alot!

Danny
 
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I don't know if there is a general formula, but if you fix the first circle at a certain point along the strip, you can calculate the distances between the successive circles iteratively. Take a look at the image I attached. Fixing the first circle defines the angle \theta_1. That first intersection is the only one you have to measure. If R is the radius of the circles (I guess .5" in your case?), then the distance between circles 1 and 2 is

d_{12} = 2 R \cos \theta_1

To find \theta_2, you can use the known slope "m" of the half-depth line. Just compute "rise over run" from the first intersection (circles 1 and 2) to the second (circles 2 and 3):

m = \frac{\Delta y}{\Delta x} = \frac{R\sin \theta_1 - R\sin \theta_2}{R\cos \theta_1 + R\cos \theta_2} = \frac{\sin \theta_1 - \sqrt{1 - \cos^2 \theta_2}}{\cos \theta_1 + \cos \theta_2}

Since \theta_1 is known, you can solve this quadratic equation for \cos \theta_2. Then the distance between circles 2 and 3 is

d_{23} = 2R \cos \theta_2

You can repeat this process to get the successive distances. This seems awfully tedious though. Maybe someone else will be inspired to come up with a better way.
 

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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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