Help needed with Elliptic Integrals

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TerryW
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Homework Statement
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I want to find the solution to the integral

##\theta = \int_0^{\theta}\frac{du}{\sqrt{(c-u^2 +2u^3)}}##

I can see that ##\frac{d^2u}{d\theta^2} = A +Bu+Cu^2## is a Weierstrass elliptic function, which can be generated from ##\Large(\normalsize\frac{du}{d\theta}\Large)\normalsize^2 = c-u^2 +2u^3## (A = 0, B=-1, C=3)

So does this make my integral an elliptic integral? I haven't been able to find a table of integrals anywhere which contains an integral of this form so I'm a bit stuck.

TerryW
 
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TerryW said:
I want to find the solution to the integral

##\theta = \int_0^{\theta}\frac{du}{\sqrt{(c-u^2 +2u^3)}}##
Mathematica can evaluate the indefinite integral on the right side:
1763578468428.webp

Here, ##\text{EllipticF}\left[\phi,m\right]## is the elliptic integral of the 1rst kind ##F\left(\phi\mid m\right)## and the ##r_k## are the 3 roots of the cubic polynomial equation ##c-r^2+2\,r^3=0##. According to the documentation, the roots are indexed as follows:
"The root indexing representation ##\text{Root}\left[f,k\right]## applies to polynomial functions ##f## only. The indexing of roots takes the real roots first, in increasing order. For polynomials with rational coefficients, the complex conjugate pairs of roots have consecutive indices."
 
So is there some elegant way to do this or am I just supposed to follow my nose and sub the Taylor expansions for terms in the two boost matrices under the assumption ##v,w\ll 1##, then do three ugly matrix multiplications and get some horrifying kludge for ##R## and show that the product of ##R## and its transpose is the identity matrix with det(R)=1? Without loss of generality I made ##\mathbf{v}## point along the x-axis and since ##\mathbf{v}\cdot\mathbf{w} = 0## I set ##w_1 = 0## to...

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