Help on simple-looking ineqality

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The discussion centers on proving the inequality: 2[(n-1) ∑_{j=1}^n r_j^2 - (n-2) r_n^2] ≥ (∑_{j=1}^n r_j)^2 for n ≥ 2 and r_j ≥ 0. Participants clarified the non-negativity of terms and provided a structured proof involving the Cauchy-Schwarz inequality. The proof demonstrates that the left-hand side simplifies to a form that confirms the inequality holds true for the specified conditions.

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phonic
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Dear all,

I come across to a simple-looking ineqality. But I cann't prove it for quite a long time. Could anybody give a hint? Thanks a lot!

[tex] 2[(n-1) \sum_{j=1}^n r_j^2 -(n-2) r_n^2] \geq (\sum_{j=1}^n r_j)^2[/tex]

where [tex]n\geq 2, \forall r_j \geq 0, j=1,2,\cdots,n[/tex].
 
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Are you saying that you do not understand why (n-3)2rn2 should be non-negative?
 
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Thanks for your sugestions. However, I still don't know how did you get to the simpification of [tex](n-3)^2r_n^2[/tex].

According to your sugestions, I got the following proof:

[tex] 2[(n-1)\sum_{j=1}^n r_j^2 -(n-2) r_n^2]<br /> =2[(n-1)\sum_{j=1}^{n-1} r_j^2 + r_n^2]<br /> \geq 2[(\sum_{j=1}^{n-1} r_j)^2 + r_n^2]<br /> \geq (\sum_{j=1}^{n-1} r_j)^2 + r_n^2 + 2r_n \sum_{j=1}^{n-1} r_j<br /> =(\sum_{j=1}^{n} r_j)^2[/tex]
 

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